Digit Wood

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Task
Given an integer, , perform the following conditional actions:

If is odd, print Weird
If is even and in the inclusive range of to , print Not Weird
If is even and in the inclusive range of to , print Weird
If is even and greater than , print Not Weird
Complete the stub code provided in your editor to print whether or not is weird.

Input Format

A single line containing a positive integer, .

Constraints

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3
Sample Output 0

Weird
Sample Input 1

24
Sample Output 1

Not Weird
Explanation

Sample Case 0:n=3
n is odd and odd numbers are weird, so we print Weird.

Sample Case 1:n=24
n > 20 and n is even, so it isn’t weird. Thus, we print Not Weird.

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {

    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {
        int n = scanner.nextInt();

        if (n % 2 != 0) {
            System.out.println("Weird");
        } else if (n > 20 && n % 2 == 0) {
            System.out.println("Not Weird");
        } else if (n > 2 && n < 5 && n % 2 == 0) {
            System.out.println("Not Weird");
        } else {
            System.out.println("Weird");
        }

    }

}

Output:

Input (stdin)
3
Your Output (stdout)
Weird
Expected Output
Weird

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